Application:
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1.1 Start Date : Thu, 17 Aug 2006 11:48:49 +0700
1.2 Name/Description: HOSMy.exe
1.3 Version Number : 2.49.8.12
1.4 Parameters :
1.5 Compilation Date: Sun, 13 Aug 2006 15:06:18 +0700
Exception:
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2.1 Date : Thu, 17 Aug 2006 12:22:42 +0700
2.2 Address: 005E4435
2.3 Module : HOSMy.exe
2.4 Type : EZSQLException
2.5 Message: SQL Error: Unknown column 'income_group2' in 'where clause'.
Active Controls:
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3.1 Form Class : TOffice97Balloon
3.2 Form Text : Save Data
3.3 Control Class: TOffice97Balloon
3.4 Control Text : Save Data
Computer:
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4.1 Name : PHARMACY01
4.2 User : Admin
4.3 Total Memory : 511 Mb
4.4 Free Memory : 89 Mb
4.5 Total Disk : 70.76 Gb
4.6 Free Disk : 60.69 Gb
4.7 System Up Time: 4 hours, 17 minutes, 33 seconds
4.8 Processor : Intel(R) Pentium(R) 4 CPU 3.06GHz
4.9 Display Mode : 1024 x 768, 32 bit
Operating System:
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5.1 Type : Microsoft Windows XP
5.2 Build # : 2600
5.3 Update : Service Pack 2
5.4 Language: Thai
Network:
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6.1 IP Address: 192.168.001.011
6.2 Submask : 255.255.255.000
6.3 Gateway : 192.168.001.001
6.4 DNS 1 : 203.147.000.002
6.5 DNS 2 : 000.000.000.000
6.6 DHCP : OFF
Other Information:
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7.1 : Hospital Code = 11435 [รพช. ตากใบ]
Database Type = MySQL
Database Protocol = mysql-4.1
Last 3 SQL Statement
.
No 1 = select income from income where income_group2='1'
.
No 2 = SHOW KEYS FROM hos.income_report2
No 3 = SHOW COLUMNS FROM hos.income_report2 LIKE '%'
Server variable
หัวข้อ: ห้องจ่ายเงิน บันทึกแล้วขึ้น ERROR ขอความช่วยเหลือด่วน (อ่าน 5051 ครั้ง)