select concat(p.pname,p.fname," ",p.lname) as ptname,g.lab_items_group_name,
d.name as request_doctor_name,
h.*,l.*,i.lab_items_unit,i.lab_items_normal_value ,i.lab_items_name
from lab_head h
left outer join lab_order l on l.lab_order_number=h.lab_order_number and l.lab_order_result IS NOT NULL and l.lab_order_result<>''
left outer join lab_items i on i.lab_items_code=l.lab_items_code
left outer join patient p on p.hn=h.hn
left outer join doctor d on d.code=h.doctor_code
left outer join lab_items_group g on g.lab_items_group_code = i.lab_items_group
where h.lab_order_number = 245
order by i.lab_items_group,i.display_order,i.lab_items_name
หัวข้อ: อยากเขียน Lab report แยกอีกรายงาน (อ่าน 7849 ครั้ง)